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Bow-X, Bow-Y, MaxBow-XY
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\( \text { Shape }=\text { CntThk }-\frac{\sum_{i:=1}^{n(\text { Shape })} \operatorname{Th} k(\text { Shape }(i))}{n(\text { Shape })} \)
\(\text { Bow }-X=C-\frac{A+B}{2}\)
The biggest value is MaxBow-XY.
\( \text { Bow }-Y=C-\frac{D+E}{2} \)
𝑀𝑎𝑥𝐵𝑜𝑤−𝑋𝑌=𝑀𝐴𝑋[𝐵𝑜𝑤−𝑋;𝐵𝑜𝑤−𝑌]
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